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Titration Worksheet with Answers (Grade 11 Chemistry)

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📄 Titration Worksheet with Answers (Grade 11 Chemistry)

A free printable acid-base titration worksheet for Grade 11 chemistry.

This free titration worksheet takes students through an acid-base titration from the lab bench to the final calculation. They learn the vocabulary, balance neutralization equations, read drawn burette scales at the meniscus, and average concordant titres from a results table.

The calculation section covers 1:1 and 1:2 mole ratios, including H₂SO₄ and Ca(OH)₂. Students finish by reading a titration curve and choosing the right indicator. Every number in the answer key, including the curve itself, was calculated and checked.

  • Grade 11 Chemistry
  • 22 marks
  • 45–60 minutes
  • Full answer key

What's in This Titration Worksheet

PartSkill practisedMarks
ATitration vocabulary3
BNeutralization equations3
CReading a burette and concordant titres3
DTitration calculations (1:1 and 1:2 ratios)7
ETitration curve and indicators4
FSpot the mistake2

It supports the Ontario Grade 11 chemistry curriculum expectations in the Solutions and Solubility unit.

Titration Vocabulary

TermMeaning
TitrantThe solution of known concentration added from the burette
AnalyteThe solution of unknown concentration in the flask
BuretteA long graduated tube with a tap, used to add solution drop by drop
Equivalence pointThe point where moles of acid and base have reacted exactly, according to the equation
End pointThe point where the indicator changes colour
Standard solutionA solution whose concentration is known accurately

In a titration, a standard solution (the titrant) is added from a burette to a measured volume of the analyte until the reaction is complete. For background, see titration on Wikipedia.

Reading a Burette

Initial123Final242526

A burette reads from the top down. Read at eye level, at the bottom of the meniscus, to the nearest 0.05 mL. In Part C of the titration worksheet, the initial reading is 1.20 mL and the final reading is 24.65 mL, so 23.45 mL of NaOH was added. Students then average the concordant titres (23.45, 23.40 and 23.45 mL) to get 23.43 mL, leaving out the rough trial.

Titration Calculations

Every titration calculation follows the same three steps:

  1. Moles of titrant: n = c × V (volume in litres).
  2. Use the mole ratio from the balanced equation.
  3. Concentration of analyte: c = n ÷ V.

For example, if 18.40 mL of 0.150 mol/L NaOH neutralizes 25.00 mL of HCl, then n(NaOH) = 0.002760 mol = n(HCl), and [HCl] = 0.002760 ÷ 0.02500 = 0.110 mol/L. With H₂SO₄, the ratio is 1 : 2, so divide the moles of NaOH by 2. The molarity worksheet reviews n = c × V, and the limiting reactant worksheet practises mole ratios.

Titration Curves and Indicators

0246810121401020304050Volume of NaOH added (mL)pH

When 0.100 mol/L NaOH is added to 25.0 mL of 0.100 mol/L HCl, the pH starts at 1.00, rises slowly, then jumps sharply at the equivalence point (25.0 mL, pH 7). A good indicator changes colour inside that jump.

IndicatorpH rangeColour change
Methyl orange3.1–4.4red → yellow
Bromothymol blue6.0–7.6yellow → blue
Phenolphthalein8.2–10.0colourless → pink

For a strong acid–strong base titration, bromothymol blue changes right at pH 7. The pH calculations worksheet shows how each point on the curve is calculated.

Titration Worksheet Practice Questions

These questions match the titration worksheet PDF, which has full-size burette diagrams, the results table and ruled working space.

Part A – Titration Vocabulary

Questions 1–6: match each term to its meaning.

  1. Titrant
  2. Analyte
  3. Burette
  4. Equivalence point
  5. End point
  6. Standard solution

Part B – Neutralization Equations

  1. Complete and balance: HCl + NaOH →
  2. Complete and balance: H₂SO₄ + KOH →
  3. Complete and balance: HNO₃ + Ca(OH)₂ →

Part C – Reading a Burette

  1. Read both burettes and record the volume of NaOH added in Trial 1.
  2. Why is the rough trial left out of the average?
  3. Calculate the average volume of the concordant trials.

Part D – Titration Calculations

  1. 25.00 mL of HCl is neutralized by 18.40 mL of 0.150 mol/L NaOH. Find the concentration of the HCl. (2 marks)
  2. 20.00 mL of H₂SO₄ is neutralized by 32.50 mL of 0.100 mol/L NaOH. Find [H₂SO₄]. (H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O) (2 marks)
  3. What volume of 0.250 mol/L HCl is needed to neutralize 15.0 mL of 0.400 mol/L NaOH?
  4. What volume of 0.200 mol/L HCl is needed to neutralize 0.500 g of Ca(OH)₂? (2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O; M = 74.10 g/mol) (2 marks)

Part E – The Titration Curve

  1. What volume of NaOH is needed to reach the equivalence point?
  2. What is the pH at the equivalence point? Why?
  3. What is the pH before any NaOH is added?
  4. Which indicator in the table is the best choice for this titration? Explain.

Part F – Spot the Mistake

  1. A student says: “At the end point, the volume of acid always equals the volume of base.” Explain the error and correct it.
  2. A student rinses the burette with distilled water and then fills it with NaOH. Explain the error and correct it.

Titration Worksheet Answer Key

Open each part of the titration worksheet answers to check your work. The printable key is at the end of the PDF.

Part A answers (Q1–6)
  1. Titrant: c
  2. Analyte: e
  3. Burette: f
  4. Equivalence point: a
  5. End point: d
  6. Standard solution: b
Part B answers (Q7–9)
  1. HCl + NaOH → NaCl + H₂O
  2. H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
  3. 2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O
Part C answers (Q10–12)
  1. 23.45 mL (24.65 − 1.20)
  2. It is a quick trial that overshoots the end point.
  3. 23.43 mL
Part D answers (Q13–16)
  1. n(NaOH) = 0.150 × 0.01840 = 0.002760 mol = n(HCl) (1 : 1); c = 0.002760 ÷ 0.02500 L = 0.110 mol/L
  2. n(NaOH) = 0.003250 mol; n(H₂SO₄) = ½ × 0.003250 = 0.001625 mol; c = 0.001625 ÷ 0.02000 L = 0.0813 mol/L
  3. n = 0.400 × 0.0150 = 0.00600 mol; V = 0.00600 ÷ 0.250 = 0.0240 L = 24.0 mL
  4. n(Ca(OH)₂) = 0.500 ÷ 74.10 = 0.006748 mol; n(HCl) = 2 × that = 0.01350 mol; V = 0.01350 ÷ 0.200 = 67.5 mL
Part E answers (Q17–20)
  1. 25.0 mL (where the curve rises steeply)
  2. pH 7: a strong acid and strong base make a neutral salt (NaCl) and water.
  3. pH 1.00 (0.100 mol/L HCl, so [H⁺] = 0.100)
  4. Bromothymol blue: its colour change (pH 6.0–7.6) includes the equivalence point at pH 7.
Part F answers (Q21–22)
  1. Only moles are related, and by the mole ratio in the equation. Volumes are equal only if the concentrations and ratio make them so (e.g. H₂SO₄ needs twice the moles of NaOH).
  2. The leftover water dilutes the NaOH, so more is needed and the calculated concentration is too high. Rinse with the NaOH solution.

5 Common Titration Mistakes

  1. Using millilitres in n = c × V. Convert to litres first.
  2. Ignoring the mole ratio. H₂SO₄ and Ca(OH)₂ need a 1 : 2 or 2 : 1 ratio.
  3. Reading the burette upside down. The scale increases downward.
  4. Averaging the rough trial. Use only concordant results.
  5. Rinsing the burette with water. Rinse with the titrant so it isn't diluted.

How to Use This Titration Worksheet in Class

  • Pre-lab: Parts A–C of the titration worksheet before students handle burettes.
  • Post-lab: Parts D–F, then have students repeat the calculation with their own titration data.
  • Extension: Sketch how the curve would change for a weak acid such as vinegar.

Review with the acids and bases quiz and the acids, bases and pH scale quiz.

Frequently Asked Questions

Is this titration worksheet free?

Yes. The worksheet and its answer key are free to download and print as a PDF, with no account needed.

How do you calculate concentration from a titration?

Find the moles of titrant with n = c × V, use the mole ratio from the balanced equation to get the moles of analyte, then divide by the analyte volume in litres.

What is the difference between the equivalence point and the end point?

The equivalence point is where the acid and base have reacted in exactly the ratio of the equation. The end point is where the indicator changes colour. A good indicator makes them almost the same.

What are concordant titres?

Concordant titres are repeat results that agree closely, usually within 0.10 mL. Only these are averaged; the rough first trial is left out.

What grade is this titration worksheet for?

It is written for Grade 11 chemistry (the Solutions and Solubility unit) and works as review for Grade 12 chemistry.

More Free Grade 11 Chemistry Resources

Ready to start? Download the free titration worksheet PDF (use the Download button above), print it double-sided, and keep the answer key pages for marking.